Пример реализции получения короткого имени файла на C#

Исходный код примера: ShortFileName.zip

using System;
using System.Runtime.InteropServices;
using System.Text;
 
namespace ShortFileName
{
      class Class1
      {
        [STAThread]
        static void Main(string[] args)
        {
            //
            // Из длинного в короткое
            //
            StringBuilder shortPath = new StringBuilder(255);
            GetShortPathName(
              @"C:\Documents and Settings\All Users\Application Data\desktop.ini", 
                     shortPath, shortPath.Capacity);
            Console.WriteLine(shortPath.ToString());
 
            //
            // Из короткого в длинное
            //
            StringBuilder longPath = new StringBuilder(255);
 
            GetLongPathName(shortPath.ToString(), longPath, longPath.Capacity);
            Console.WriteLine(longPath.ToString());
 
            Console.ReadLine();
        }
 
        // Функции из kernel32
 
            [DllImport("kernel32.dll", CharSet = CharSet.Auto)]
            public static extern int GetLongPathName(
                  [MarshalAs(UnmanagedType.LPTStr)]
                  string path,
                  [MarshalAs(UnmanagedType.LPTStr)]
                  StringBuilder longPath,
                  int longPathLength
            );
 
            [DllImport("kernel32.dll", CharSet = CharSet.Auto)]
            public static extern int GetShortPathName(
                  [MarshalAs(UnmanagedType.LPTStr)]
                  string path,
                  [MarshalAs(UnmanagedType.LPTStr)]
                  StringBuilder shortPath,
                  int shortPathLength
            );
 
 
      }
}